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-1x^2+2=12x-7
We move all terms to the left:
-1x^2+2-(12x-7)=0
We get rid of parentheses
-1x^2-12x+7+2=0
We add all the numbers together, and all the variables
-1x^2-12x+9=0
a = -1; b = -12; c = +9;
Δ = b2-4ac
Δ = -122-4·(-1)·9
Δ = 180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{180}=\sqrt{36*5}=\sqrt{36}*\sqrt{5}=6\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-6\sqrt{5}}{2*-1}=\frac{12-6\sqrt{5}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+6\sqrt{5}}{2*-1}=\frac{12+6\sqrt{5}}{-2} $
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